Gaseous methane (CH4) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O) If 0.391 g of carbon dioxide is produced from the reaction of 0.16 g of methane and 0.84 g of oxygen gas, calculate the percent yield of carbon dioxide.

Question

Chemistry

Young

1 August, 10:33

Gaseous methane (CH4) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O) If 0.391 g of carbon dioxide is produced from the reaction of 0.16 g of methane and 0.84 g of oxygen gas, calculate the percent yield of carbon dioxide.

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Answers (2)

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Emelia Solis · Answer 1

The % yied of carbon dioxide = 89.1 %

Explanation:

Step 1: Data given

Mass of CO2 = 0.391 grams

Mass of methane = 0.16 grams

Mass of oxygen gas = 0.84 grams

Molar mass of CO2 = 44.01 g/mol

Molar mass of methane (CH4) = 16.04 g/mol

Molar mass of oxygen gas (O2) = 32 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (g)

Step 3: Calculate moles of CH4

Moles CH4 = mass CH4 / Molar mass CH4

Moles CH4 = 0.16 grams / 16.04 g/mol

Moles CH4 = 0.00998 mol

Step 4: Calculate moles of O2

Moles O2 = mass O2 / Molar mass O2

Moles O2 = 0.84 grams / 32 g/mol

Moles O2 = 0.02625 mol

Step 5: Calculate limiting reactant

For 1 mole CH4 consumed, we need 2 moles O2, to produce 1 mole of CO2

CH4 is the limiting reactant. It will completely be consumed (0.00998 moles)

O2 is in excess. There will be consumed 2*0.00998 = 0.01996 mol

There will remain 0.02625 - 0.01996 = 0.00629 mol O2

Step 6: Calculate moles carbon dioxide

For 1 mole CH4 consumed, we need 2 moles O2, to produce 1 mole of CO2

For 0.00998 moles of CH4, we have 0.00998 moles of CO2

Step 7: Calculate theoretical mass of CO2

Mass of CO2 = moles of CO2 * Molar mass of CO2

Mass of CO2 = 0.00998 moles * 44.01 g/mol

Mass of CO2 = 0.439 grams

Step 8: Calculate the % tield of CO2

% yield = actual yield / theoretical yield

% yield = (0.391 grams / 0.439 grams) * 100%

% yield = 89.1%

The % yied of carbon dioxide = 89.1 %

Demarcus · Answer 2

percent yield of carbon dioxide is 46.5 %

Explanation:

Formula for the above reaction is

CH₄+2O₂→CO₂+2H₂OCH₄+2O₂→CO₂+2H₂O

Firstly I will calculate the moles of reactants

Moles of CH₄ = given mass / Molar mass = 0.16g / 16gmole=0.01 moles of CH₄ (limiting reactant)

Moles of Oxygen O₂ = given mass / Molar mass = 0.84 g/32gmole=0.026 moles of O₂ (reactant in excess)

Thus, moles of CO₂ = 0.01

Mass of CO₂ = 0.01 mole * 44 g mole=0. 44 grams

Therefore,

For percent yield=experimental yield / theoretical yield*100%.

% yield = 0.391g/0.84*100%=46.5 %