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29 September, 06:40

What volume (L) would be produced from 1.5x1025 molecules of CO2 at STP?

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Answers (1)
  1. 29 September, 07:03
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    557.7 L

    Explanation:

    1 mol → 6.02*10²³ molecules at STP produces 22.4L

    Therefore, we need to know how many moles are 1.5 * 10²⁵ molecules

    (1.5 * 10²⁵ molecules / 6.02*10²³ molecules). 1 mol = 24.9 moles

    Let's make a rule of three:

    1 mol can produce at STP a volume of 22.4 L

    24.9 moles may produce at STP a volume of (24.9. 22.4) / 1 = 557.7 L

    Let's verify by the Ideal Gases Law

    P. V = n. R. T → V = (n. R. T) / P

    STP → Pressure = 1 atm, T = 273 K

    V = (24.9 mol. 0.082 L. atm/mol. K. 273 K) / 1 atm → 557.4 L
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