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10 April, 15:29

The value of ΔG°′ for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is + 7.53 kJ/mol. If the concentration of dihydroxyacetone phosphate at equilibrium is 1.85 mM 1.85 mM, what is the concentration of glyceraldehyde-3-phosphate? Assume a temperature of 25.0°C.

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  1. 10 April, 16:22
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    Concentration of glyceraldehyde-3-phosphate is 0.0886mM

    Explanation:

    Get K from the expression exp (ΔG/-RT) = K

    Where

    ΔG = Gibbs free energy = 7.53 kJ / mol = 7.53 * 10^3 J/mol

    T = 250C = 273 + 25 = 298 K

    R = 8.3145 J (mol. K)

    K = exp (7530 / (-298*8.3145)

    K = 4.79*10^-2

    NB: K = (conc of products) / (conc of reactants)

    From the question

    dihydroxyacetone phosphate is the reactant while glyceraldehyde-3-phosphate is the product

    4.70*10^-2 = (conc. Of products/1.85mM)

    Conc of products = (4.70*10^-2) * 1.85

    Conc. Of products = 0.0886mM
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