Iron and carbon monoxide are made by heating 5.53 kg of iron ore, Fe₂O₃, and carbon. What is the theoretical yield of iron in kilograms?

Mass of Fe produced = 3.86785211069 ≈ 3.87 kg

Explanation:

From the question the chemical reaction can be written as follow:

Fe2O3 + C → Fe + CO

Balance the equation

Fe2O3 + 3C → 2Fe + 3CO

compute the molecular mass of Fe2O3 and atomic mass of Iron (Fe)

Molecular mass of Fe2O3 = 55.845 (2) + 15.999 (3) = 111.69 + 47.997 = 159.687 g

Atomic mass of iron = 55.845 g

From the balanced equation

159.687 g of Fe2O3 produces 2 * 55.845 = 111.69 g of Fe (iron)

Convert the 5.53 kg to gram

1 kg = 1000 g

5.53 kg = 5.53 * 1000 = 5530 g

since,

159.687 g of Fe2O3 produces 2 * 55.845 = 111.69 g of Iron (Fe)

5530 g of Fe2O3 will produce

cross multiply

Mass of Fe produced = 5530 * 111.69/159.687

Mass of Fe produced = 617645.7

/159.687

Mass of Fe produced = 3867.85211069 g

convert to kg

1000 g = 1 kg

3867.85211069 = 3867.85211069/1000

Mass of Fe produced = 3.86785211069 ≈ 3.87 kg