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2 December, 15:08

Use the following information to determine the empirical formula if a compound is found to have 18.7% Li, 16.3% C, and 65.5% O Answer questions 4-6 with this data

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  1. 2 December, 16:40
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    The empirical formula is Li2CO3

    Explanation:

    Step 1: Data given

    Suppose the mass of the compound = 100 grams

    The compound contains:

    18.7% Li = 18.7 grams of Li

    16.3 % C = 16.3 grams of C

    65.0% O = 65.0 grams of O

    Total = 100%

    Molar mass of Li = 6.94 g/mol

    Molar mass of C = 12.01 g/mol

    Molar mass of O = 16 g/mol

    Step 2: Calculate moles

    Moles = Mass / molar mass

    Moles Li = 18.7 grams / 6.94 g/mol = 2.65 moles

    Moles C = 16.3 grams / 12.01 = 1.36 moles

    Moles O = 65.0 grams / 16.0 g/mol = 4.06 moles

    Step 3: Calculate the mol ratio

    We divide by the smallest number of moles

    Li: 2.65/1.36 ≈ 2

    C: 1.36/1.36 = 1

    O: 4.06/1.36 ≈ 3

    The empirical formula is Li2CO3
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