A 5.00 liter gas sample is collected at a temperature and pressure of 27.0 degree C and 1.20 atm. It is desired to transfer the gas to a 3.00 liter container at a pressure of 1.00 atm. What must be the temperature of the gas in the 3.00 liter container?

a) 417 K

b) 216 K

c) 13.5 degree C

d) 150 K

The temperature of the gas in the 3.00 liter container, must be 150K

Explanation:

Let's apply the Ideal Gas Law, to find out the moles

P. V = n. R. T

1,20 atm. 5L = n. 0,082 L. atm/mol. K. 300 K

(1,20 atm. 5L) / (0,082 mol. K/L. atm. 300 K) = n

6/24,6 mol = n = 0,244 moles

We have the moles now, so let's find the temperature in our new conditions.

P. V = n. R. T

1 atm. 3L = 0,244 moles. 0,082 L. atm/mol. K. T° in K

(1 atm. 3L / 0,244 moles. 0,082 mol. K/L. atm) = T° in K

3/20,008 K = T° in K = 150K