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27 March, 22:54

What is the molality of a solution prepared by dissolving 86.9 g of diethyl ether, C4H10O, in 425 g of benzene, C6H6?

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Answers (2)
  1. 27 March, 23:13
    0
    Molality is 2.76 m/kg

    Explanation:

    First of all, determinate the moles of solute by dividing mass / molar mass

    Molar mass diethyl ether = 74.12 g/m

    86.9 g / 74.12 g/m = 1.17 moles

    This moles of solute, are in 425 grams of benzene (solvent)

    Molality means, the moles of solute which occupy 1kg of solvent.

    425 g = 0.425 kg

    1.17 m / 0.425 kg = 2.76 m
  2. 27 March, 23:54
    0
    The molality of this solution is 2.75 molal

    Explanation:

    Step 1: Data given

    Mass of diethyl ether = 86.9 grams

    Mass of benzene = 425 grams = 0.425 kg

    Step 2: Calculate moles of solute

    Molality = moles of solute/kg of solvent

    Molar mass of C4H10O =

    4 * molar mass carbon + 10 * molar mass hydrogen + molar mass of oxygen

    molar mass C4H10O = 74.12 g/mol

    Moles solute (C4H10O) = 86.9 grams / 74.12 g/mol

    Moles C4H10O = 1.17 moles

    Step 3: Calculate molality

    Molality = 1.17 moles of C4H10O / 0.425 kg of C6H6

    Molality = 2.75 mol/kg = 2.75 molal

    The molality of this solution is 2.75 molal
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