How much carbon dioxide in kilograms is produced upon the complete combustion of 29.4 L of propane (approximate contents of one 5-gal tank) ? Assume that the density of the liquid propane in the tank is 0.621 g / mL.

61kg

Explanation:

Like all other hydrocarbons, the combustion of propane will yield water and carbon iv oxide.

Let's write a complete and balanced chemical equation for this.

C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (l)

Now, we first convert the information into a mass.

We know that mass = density * volume

Let's convert the volume here into ml since density is in mL. It must be remembered that 1000ml = 1L. Hence, 29.4L = 29,400ml

The mass is thus = 0.6921 * 29,400 = 20,347.74g

Now from the balanced equation, we can see that one mole of propane produced 3 moles of carbon iv oxide. This is the theoretical relation.

Let's now calculate the actual number of moles. The number of moles of propane produced is the mass of propane divided by the molar mass of propane. The molar mass of propane is 3 (12) + 8 (1) = 36 + 8 = 44g/mol

The number of moles = 20,347.74/44 = 462.44

We simply multiply this number by 3 to get the actual number of moles of carbon dioxide produced. This is equals 1387.35 moles

Since we know this, we now calculate the mass of carbon iv oxide produced. The mass is equals the number of moles multiplied by the molar mass. The molar mass of carbon iv oxide is 44g/mol.

The mass produced is thus 1387.35 * 44 = 61,043g

To get the kilogram equivalent, we simply divide by 1000 = 61,043/1000 = 61kg