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23 February, 20:16

Assuming all volume measurements are made at the same temperature and pressure, what volume of hydrogen gas is needed to react completely with 4.55 L of oxygen gas to produce water vapor?

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  1. 23 February, 23:01
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    9.1L

    Explanation:

    Firstly, to solve the problem, we need a balanced chemical equation.

    2H2 + O2 - --> 2H2O

    2 moles of hydrogen reacted one mole of oxygen. Now, we know that at STP, one mole of a gas occupies a volume of 22.4L, now let us get the number of moles in 4.55L of oxygen.

    This means 4.55/22.4 = 0.203125 mole

    Since in theory we have 2 moles of hydrogen reacting one mole of oxygen. Hence the number of moles of hydrogen we have is 0.203125 * 2 = 0.40625 mole

    We now proceed to get the volume of hydrogen gas. Since 1 mole is 22.4L, then

    0.40625 Is 0.40625 * 22.4 = 9.1L
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