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31 December, 15:03

How many moles of are in 179 mL of a 3.0 M of CaCl2 solution?

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  1. 31 December, 17:43
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    Answer: 0.537 moles

    Explanation:

    Hello, Let's first explain the term molarity

    ---> Molarity is the most commonly used term to describe the concentration of a solution. It is equal to the moles of solute divided by the liters of solution.

    ---> The solute is defined as the substance being dissolved, while the solvent is the substance where the solute is dissolved (usually water).

    ---> The solution is the combination of the solute and the solvent.

    Molarity = moles of solution/Liters of

    solution

    Parameters given are

    Volume (V) = 179ml of CaCl2 solution

    Molarity = 3.0m

    Therefore,

    Molarity = number of moles of CaCl2 solution / Volume of CaCl2 in Liters (eqn 1)

    First, convert 179ml to liters

    1ml = 0.001L

    179ml = ?

    179ml = 179ml x 0.001L

    = 0.179L

    From (eqn 1)

    Let the number of moles of CaCl2 solution be M

    => 3 = M/0.179

    M = 0.179 x 3

    = 0.537 moles

    Hence the number of moles in 179ml of CaCl2 solution yields 0.537 moles
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