An experiment requires 47.9 g g of ethylene glycol, a liquid whose density in SI units is 1114 kg/m3 k g / m 3. Rather than weigh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume in milliliters of the liquid should be used?

43 mL would be the volume in milliliters of the liquid that should be used

Explanation:

Ethylene glycol density = 1114 kg/m³

Mass of ethylene glycol density = 47.9 g

Let's convert the density to units of g/mL

1 cm³ = 1mL

1 kg = 1000 g

1m³ = 1000000 cm³

1114 kg. 1000 g / 1kg = 1114000 g

Ethylene glycol density = 1114000 g / 1000000 cm³ = 1.114 g/mL

Now we can apply the mass, to determine the volume in mL

Ethylene glycol density = Ehtylene glycol mass / Ethylene gylocl volume

1.114 g/mL = 47.9 g / Ethylene gylocl volume

Ethylene gylocl volume = 47.9 g / 1.114 g/mL → 42.99 mL ≅ 43mL