A sample of neon initially has a volume of 2.50 L at 15 degrees Celsius. What is final temperature, in degrees Celsius, is needed to change the volume of the gas to 1.25 L?

-129°C

Explanation:

First, we analyze what was given from the question as follows:

V1 = 2.50L

T1 = 15°C = 15 + 273 = 288K

V2 = 1.25L

T2 = ?

V1 / T1 = V2 / T2

2.5/288 = 1.25/T2

Cross multiply to express in linear form

2.5 x T2 = 288 x 1.25

Divide both side by the coefficient of T2 i. e 2.5

T2 = (288 x 1.25) / 2.5

T2 = 144K

Converting this temperature (144K) to degree Celsius, we have

T°C = K - 273

T°C = 144 - 273

T°C = - 129°C