A balloon occupies a volume of 44 L at 200K, what will the temperature of the balloon become if it is changed to 500K?

110L

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 44L

Initial temperature (T1) = 200K

Final temperature (T2) = 500K

Final volume (V2) = ... ?

The new volume of the balloon can be obtained by using Charles' law equation as shown below:

V1/T1 = V2/T2

44/200 = V2/500

Cross multiply

200 x V2 = 44 x 500

Divide both side by 200

V2 = 44 x 500/200

V2 = 110L

Therefore, the new volume of the balloon is 110L