A 15.85g piece of iron absorbs 1086.75 joules of heat energy and its temperature changes from 25 degrees Celsius to 175 degrees celcius. Calculate the specific heat capacity of iron.

Specific heat capacity of iron is the amount of heat required to raise 1g of iron by 1 degree Celsius.

The formula is Q=mc∆T

Where Q is energy in joules.

M is mass in gram.

C is specific heat capacity in J/g°C.

∆T is change in temperature in degree Celsius

Q=1086.75joules

M=15.85g

C=?

∆T = final T-initial T (175-25) = 150°c.

Q=Mc∆T

1086.75 = 15.85*C*150

1086.85=2377.5c

C=1086.85:2377.5

C=0.46J/g°C.