Ask Question
29 May, 04:36

The terms Q and K describe mass action for reactions at non-equilibrium and equilibrium conditions, respectively. For a forward reaction to being favored in a living cell, which of the following statements must be true?

a. The value of K must be less than that of Q.

b. The value of Q must be less than that of K.

c. No conclusion can be drawn about Q and K for a favorable process.

d. None of the listed statements are true; cells are at equilibrium.

+5
Answers (1)
  1. 29 May, 06:40
    0
    Q should be less than K for the forward reaction to be favoured (option C)

    Explanation:

    Since the standard gibbs free energy is

    ΔG = ΔG⁰ + RT*ln Q

    where Q = [P1]ᵃ ... / ([R1]ᵇ ...), representing the ratio of the product of concentration of chemical reaction products P and the product of concentration of chemical reaction reactants R

    when the system reaches equilibrium ΔG=0 and Q=Keq

    0 = ΔG⁰ + RT*ln Q → ΔG⁰ = (-RT*ln Keq)

    therefore the first equation also can be expressed as

    ΔG = RT*ln (Q/Keq)

    since R and T are always positive:

    ΔG<0 if Q0 if Q>Keq (thus the reverse reaction is favoured)

    therefore Q should be less than K for the forward reaction to be favoured
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The terms Q and K describe mass action for reactions at non-equilibrium and equilibrium conditions, respectively. For a forward reaction to ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers