How many grams of lithium nitride needs to react with excess water at stp to produce 15.0 l of ammonia

Mass = 24.4 g

Explanation:

Given dа ta:

Mass of lithium nitride needed = ?

Volume of ammonia = 15.0 L

Solution:

Chemical equation:

Li₃N + 3H₂O → NH₃ + 3LiOH

One mole = 22.414 L

We will compare the volume of lithium nitride and ammonia.

NH₃ : Li₃N

22.414 : 22.414

15.0 : 15.0

Number of moles of lithium nitride:

PV = nRT

n = 1 atm * 15 L / 0.0821 atm. L / mol. K * 273 K

n = 15 / 22.41 / mol

n = 0.7

Mass of Lithium nitride:

Mass = number of moles * molar mass

Mass = 0.7 mol * 34.83 g/mol

Mass = 24.4 g