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6 December, 17:24

An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to - 5°C. Assume that there is no volume change in the tire.

What is the new pressure of the tire after the temperature change?

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  1. 6 December, 20:31
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    P₂ = 2.7 atm

    Explanation:

    Given dа ta:

    Initial temperature = 30°C

    Initial pressure = 3.00 atm

    Final temperature = - 5°C

    Final pressure = ?

    Solution:

    Initial temperature = 30°C = 30 + 273 = 303 K

    Final temperature = - 5°C = - 5 + 273 = 268 K

    According to Gay-Lussac Law,

    The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

    Mathematical relationship:

    P₁/T₁ = P₂/T₂

    Now we will put the values in formula:

    3.0 atm / 303 K = P₂/268 K

    P₂ = 3.0 atm * 268 K / 303 K

    P₂ = 804 atm. K / 293 K

    P₂ = 2.7 atm
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