10.0 grams of a gas occupies 12.5 liters at a pressure of 42.0 mm Hg. What is the volume when the pressure has increased to 75.0 mm Hg?

7 Liters is the new volume

Explanation:

For this problem, we assume that T° keeps on constant. Therefore we can apply Boile Mariotte's concept: pressure can be modified in a proportional indirectly way to volume

V₁. P₁ = P₂. V₂

12.5 L. 42 mmHg = 75 mmHg. V₂

(12.5 L. 42 mmHg) / 75 mmHg = V₂

7L = V₂

As the pressure has increased, the volume decreased.