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6 November, 11:32

An aqueous solution contains 1.00 g/L of a derivative of the detergent laurel alcohol. The osmotic pressure of this solution is 17.8 torr, at 25°C. What is the molar mass (in g/mol) of this detergent?

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  1. 6 November, 15:16
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    mm = 1043.33 g/mol

    Explanation:

    osmotic pressure (π):

    π = CbRT

    ∴ π = 17.8 torr = 0.0234 atm

    ∴ Cb: solute concentration

    ∴ T = 25°C = 298 K

    ∴ R = 0.082 atm. L/K. mol

    ⇒ Cb = π/RT

    ⇒ Cb = (0.0234 atm) / ((0.082 atm. L/K. mol) (298 K))

    ⇒ Cb = 9.585 E-4 mol/L

    molar mass (mm):

    ⇒ mm = (1.00 g/L) (L/9.585 E-4 mol)

    ⇒ mm = 1043.33 g/mol
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