According to the following reaction, how many grams of hydrogen peroxide (

H

2

O

2

) are necessary to form 0.182 moles oxygen gas?

hydrogen peroxide (

H

2

O

2

) (aq)

→

water (l) + oxygen (g)

12.4 g

Explanation:

Let's consider the following balanced equation.

H₂O₂ (aq) → H₂O (l) + 0.5 O₂ (g)

The molar ratio of H₂O₂ to O₂ is 1:0.5. The moles of H₂O₂ required to form 0.182 moles of O₂ are:

0.182 mol O₂ * (1 mol H₂O₂ / 0.5 mol O₂) = 0.364 mol H₂O₂

The molar mass of H₂O₂ is 34.01 g/mol. The mass of H₂O₂ corresponding to 0.364 moles is:

0.364 mol * 34.01 g/mol = 12.4 g