A student prepares a solution by dissolving 1.000 mol of Na2SO4 in water. She accidentally leaves the container uncovered and comes back the next week to find only a white, solid residue. The mass of the residue is 322.2 g. Determine the chemical formula of this residue.

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Chemistry

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13 May, 14:55

A student prepares a solution by dissolving 1.000 mol of Na2SO4 in water. She accidentally leaves the container uncovered and comes back the next week to find only a white, solid residue. The mass of the residue is 322.2 g. Determine the chemical formula of this residue.

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Answers (1)

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Adriel Duncan · Answer 1

Formula is NA2SO4•10H2O

Sodium sulfate decahydrate.

Explanation:

Sodium sulfate is soluble in water. Soduim sulphare form various hydrates, so if the solution is open to the atmosphere for a week at least a lot of the water will have evaporated leaving behind a solid hydrate of Soduim sulfate.

Mass of anhydrous Na2SO4 = molar mass * number of moles

Molar mass = (23*2) + (32*1) + (16*4)

= 146 g/mol

Mass = 146*1

= 146 g of NA2SO4

NA2SO4•nH2O - -> Na2SO4 + nH2O

Molar mass of hydrate, NA2SO4. nH2O

= (142 + 18n) g/mol

Mass of NA2SO4. nH2O = (142 + 18n) * 1

= (142 + 18n) g

Mass of the residue = 322.2 g

Therefore, 142 + 18n = 322.2

18n = 180.2

n = 10

Formula is NA2SO4•10H2O

Sodium sulfate decahydrate.

0.0588 mol MgSO4 / 0.0588 = 1 mol MgSO4

0.412 mol H2O / 0.0588 = 7 mol H2O

Formula is MgSO4•7H2O