Ask Question
9 March, 07:27

At 20 ∘C the vapor pressure of benzene C6H6 is 75 torr and that of toluene C7H8 is 22 torr. Assume that benzene and toluene form an ideal solution.

a) In a solution composed of benzene and toluene that has a vapor pressure of 37 torr at 20 ∘C, what is the mole fraction of benzene?

b) In a solution composed of benzene and toluene that has a vapor pressure of 37 torr at 20 ∘C, what is the mole fraction of toluene?

+1
Answers (1)
  1. 9 March, 11:22
    0
    a) Xbenzene = 0.283

    b) Xtoluene = 0.717

    Explanation:

    At T = 20°C:

    ⇒ vapor pressure of benzene (P*b) = 75 torr

    ⇒ vapor pressure toluene (P*t) = 22 torr

    Raoult's law:

    Pi = Xi. P*i

    ∴ Pi: partial pressure of i

    ∴ Xi: mole fraction

    ∴ P*i: vapor pressure at T

    a) solution: benzene (b) + toluene (t)

    ∴ Psln = 37 torr; at T=20°C

    ⇒ Psln = Pb + Pt

    ∴ Pb = (Xb) * (P*b)

    ∴ Pt = (Xt) * (P*t)

    ∴ Xb + Xt = 1

    ⇒ Psln = 37 torr = (Xb) (75 torr) + (1 - Xb) (22 torr)

    ⇒ 37 torr - 22 torr = (75 torr) Xb - (22 torr) Xb

    ⇒ 15 torr = 53 torrXb

    ⇒ Xb = 15 torr / 53 torr

    ⇒ Xb = 0.283

    b) Xb + Xt = 1

    ⇒ Xt = 1 - Xb

    ⇒ Xt = 1 - 0.283

    ⇒ Xt = 0.717
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “At 20 ∘C the vapor pressure of benzene C6H6 is 75 torr and that of toluene C7H8 is 22 torr. Assume that benzene and toluene form an ideal ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers