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18 July, 20:40

In part D of the experiment, a student begins with a beaker containing 10.0 mL of 0.010 M HCl solution and adds different volumes of 0.010 M NaOH. (a) How many millimoles of acid are initially in the beaker? (If in doubt, look back at your calculation from experiment 9).

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  1. 19 July, 00:25
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    There are initially 0.1 millimoles of acid (HCl) in the beaker.

    Explanation:

    Step 1: Data given

    volume of 0.010 M HCl = 10.0 mL = 0.01 L

    Step 2: Calculate the number of moles HCl

    Number of moles = Molarity HCl * volume of solution

    Number of moles HCl = 0.010 M * 0.01 L = 0.0001 moles HCl = 0.1 * 10^-3 mol = 0.1 mmol HCl

    There are initially 0.1 millimoles of acid (HCl) in the beaker.
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