A chemist dissolves 660. mg of pure hydroiodic acid in enough water to make up 300. mL of solution. Calculate the pH of the solution.

0.23

Explanation:

Mass = 600mg, Volume = 300ml

To get the number of mole of HCl

n = mass/molar mass = 600/36.5 = 18.02 mole

Now to he the concentration of HCl

C = n / v

= 18.02/300

= 0.603mol/ml

But pH = - log [hydrogen ion]

Therefore pH = - log 0.603

=0.23