How many liters are in 5.98 moles of nitrogen gas at STP?

a) 0.267 L

b) 95.7

c) 134L

d) 3.60 x 1024L

The correct answer is c) 134L

Explanation:

We use the formula PV = nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol.

1 atm x V = 5, 98 mol x 0, 082 l atm / K mol x 273 K

V = 5, 98 mol x 0, 082 l atm / K mol x 273 K / 1 atm

V = 133, 86828 l