what grade is learning What amount of thermal energy (heat) in joules required to raise the temperature of 25 grams of water from 0 degrees C to 100 degrees C?

10425 J are required

Explanation:

assuming that the water is entirely at liquid state at the beginning, the amount required is

Q = m*c * (T final - T initial)

where

m = mass of water = 25 g

T final = final temperature of water = 100°C

T initial = initial temperature of water = 0°C

c = specific heat capacities of water = 1 cal / g°C = 4.186 J/g°C (we assume that is constant during the entire temperature range)

Q = heat required

therefore

Q = m*c * (T final - T initial) = 25 g * 4.186 J/g°C * (100°C - 0°C) = 10425 J

thus 10425 J are required