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20 September, 11:42

You have two buffered solutions. Buffered solution 1 consists of 5.0 M HOAc and 5.0 M NaOAc; buffered solution 2 is made of 0.050 M HOAc and 0.050 M NaOAc. How do the pHs of the buffered solutions compare? (Note: Ac - = acetate ion, CH3COO-). A. The pH of buffered solution 1 is greater than that of buffered solution 2. B. None of the answers are correct C. The pH of buffered solution 1 is equal to that of buffered solution 2. D. The pH of buffered solution 2 is greater than that of buffered solution 1. E. Cannot be determined without the Ka values.

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  1. 20 September, 14:45
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    C

    Explanation:

    The Henderson-Hasselbalch equation relates pH to the concentrations of an weak acid-base conjugate pair as follows:

    pH = pKa + log ([A⁻]/[HA])

    For solution 1, the pH may be expressed as follows:

    pH = pKa + log (5.0M/5.0M) = pKa

    For solution 2, pH may be expressed as follows:

    pH = pKa + log (0.050M/0.050M) = pKa

    Thus, the pH values are equal to the pKa in both cases and are the same.
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