Barium has a body-centered cubic structure. If the atomic radius of barium is 222 pm, calculate the density of solid barium?

Answer: density = 3.377g/cm³

Explanation:

Density = (molecular weight * effective number of atoms per unit cell) / (volume of unit cell * avogadro constant)

D = (M * n) / (V*A)

M = 137g/mol

n = 2 (For BCC)

V=a³, where a = 4r/√3

a = (4*222) / √3

a=512.69pm

a = 512.69*10^-10cm

V = (512.69*10^-10) ^3

V = 1.3476*10^-22cm³

D = (137*2) / (1.3476*10^-22 * 6.02^23)

D = 3.377g/cm³

Therefore the density of barium is 3.377g/cm³