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25 May, 12:52

Calculate the molarity of a solution that contains 3.00 grams Na2SO4 in 25 mL of solution.

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  1. 25 May, 16:26
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    M Na2SO4 sln = 0.8448 M

    Explanation:

    molarity (M) [=] mol/L

    ∴ mass Na2SO4 = 3.00 g

    ∴ volume soln = 25 mL = 0.025 L

    ∴ molar mass Na2SO4 = 142.04 g/mol

    ⇒ mol Na2SO4 = (3.00 g) * (mol/142.04 g) = 0.02112 mol

    ⇒ M Na2SO4 sln = (0.02112 mol/0.025 L) = 0.8448 M
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