If you start with 10.0 grams of lithium hydroxide and an excess of hydrogen bromide, how many grams of lithium bromide will be produced?

grams of lithium bromide produced = 36.2642309286 ≈ 36.30 g

Explanation:

The equation of the reaction is as follows;

Lithium hydroxide + hydrogen bromide → Lithium Bromide + water

LiOH + HBr → LiBr + H2O

The equation is already balanced

Molecular mass of LiOH = 6.941 + 15.999 + 1.00784

Molecular mass of LiOH = 23.94784 g

Molecular mass of LiBr = 6.941 + 79.904 = 86.845 g

From the equation

LiOH + HBr → LiBr + H2O

23.94784 g of lithium hydroxide produces 86.845 g of lithium bromide

10 g of lithium hydroxide will produce?

cross multiply

grams of lithium bromide produced = 10 * 86.845/23.94784

grams of lithium bromide produced = 868.45/23.94784

grams of lithium bromide produced = 36.2642309286 ≈ 36.30 g