Find the mass in grams of 6.00x 10^23 molecules of C2H4O2

60.272 g

Explanation:

We are given;

Molecules of C₂H₄O₂ are 6.00 * 10^23 molecules

We are required to calculate mass of C₂H₄O₂

We know that one mole of a compound contains a number of molecules equivalent to the Avogadro's number, 6.022 * 10^23 molecules That is, 1 mole of a compound = 6.022 * 10^23 molecules

In this case;

1 mole of C₂H₄O₂ = 6.022 * 10^23 molecules

But, Molar mass of C₂H₄O₂ = 60.052 g/mol

Therefore;

60.052 g = 6.022 * 10^23 molecules

Mass of C₂H₄O₂ = (60.052 g * 6.022 * 10^23) : 6.00 * 10^23

= 60.272 g

Therefore, the mass of C₂H₄O₂ in 6.00 * 10^23 molecules is 60.272 g