What is the specific heat of a 42.6 gram compound that changes from 12 Celsius to 46 Celsius when it absorbs 1260 KJ of energy

869.93J/g°C

Explanation:

From the question given, we obtained the following:

M = 42.6g

T1 = 12°C

T2 = 46°C

ΔT = T2 - T1 = 46 - 12 = 34°C

C = ?

Q = 1260 KJ = 1260000J

Q = MCΔT

C = Q / MΔT

C = 1260000 / (42.6 x 34)

C = 869.93J/g°C

Therefore, the specific heat capacity is 869.93J/g°C