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29 April, 16:58

Balance the following expression: __ CH3CH2COOH + __ O2 → __ CO2 + __ H2O How many moles of O2 are required for the complete combustion of 6 mol of propanoic acid?

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  1. 29 April, 20:50
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    We need 21.0 moles of O2

    Explanation:

    Step 1: Data given

    Moles of propanoic acid = 6.0 moles

    CH3CH2COOH = propanoic acid

    Step 2: The balanced equation

    2CH3CH2COOH + 7O2 → 6CO2 + 6H2O

    Step 3 : Calculate moles O2

    For 2 moles propanoic acid we need 7 moles O2 to produce 6 moles CO2 and 6 moles H2O

    For 6.0 moles propanoic acid we need 6.0 * 3.5 = 21 moles O2

    We need 21.0 moles of O2
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