A sample of 3.785 g of a compound is analyzed, and found to contain 1.302 g Fe and 2.483 g Cl. Another sample of the compound is found to contain 2.329 g of Cl. How many grams of Fe will it contain

Defining law of simple multiple proportions, which states that when two or more elements form more than one compound, the ratio of the weights of one element that combine with a given weight of another element in the different compounds is a ratio of small whole numbers

Ratio of Fe and Cl in the first sample is:

Mass of Fe: Mass of Cl

1.302 : 2.483

Ratio = 1 : 1.9

Therefore, in the other sample;

Mass of Fe: Mass of Cl

= 1 : 1.9

= x : 2.329

x = 2.329 : 1.9

= 1.221 g.

1.221g

Explanation:

First Sample

Ratio of Fe and Cl is given as;

Mass of Fe: Mass of Cl

1.302g : 2.483g

Second Sample;

Mass of Fe: Mass of Cl

xg : 2.329g

The ratio between both elements is constant in both samples, so we have;

Ratio of first sample = Ratio of second sample

1.302g : 2.483g = xg : 2.329g

1.302 / 2.483 = x / 2.329

x = (2.329 * 1.302) / 2.483

x = 1.221g