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15 January, 18:39

What is the molarity in 850 ml of solution containing 63 grams of Sodium Hydroxide?

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  1. J
    15 January, 20:00
    0
    Answer: 1.85M

    Explanation:

    Sodium hydroxide has a chemical formula of NaOH

    Given that,

    Amount of moles of NaOH (n) = ?

    Mass of NaOH in grams = 63g

    For molar mass of NaOH, use the molar masses:

    Sodium, Na = 23g;

    Oxygen, O = 16g;

    Hydrogen, H = 1g

    NaOH = (23g + 16g + 1g)

    = 40g/mol

    Since, amount of moles = mass in grams / molar mass

    n = 63g / 40.0g/mol

    n = 1.575 mole

    Volume of NaOH solution (v) = 850mL

    [Convert 850mL to liters

    If 1000mL = 1L

    850mL = 850/1000 = 0.85L]

    Concentration of NaOH solution (c) = ?

    Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

    c = n / v

    c = 1.575 mole / 0.85L

    c = 1.85M [1.85M is the concentration in moles per litres which is also known as molarity]

    Thus, the molarity of the solution is 1.85M
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