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12 December, 09:32

200mL of 4.98M of sodium chloride solution is added to an additional 532 ml of water what is the final molarity?

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  1. 12 December, 11:57
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    M₂ = 1.9 M

    Explanation:

    Given data;

    Volume of sodium chloride = 200 mL

    Molarity of sodium chloride = 4.98 M

    Volume of water = 532 mL

    Final Molarity = ?

    Solution:

    M₁V₁ = M₂V₂

    M₂ = M₁V₁ / V₂

    M₂ = 4.98 M * 200 mL / 532 mL

    M₂ = 996 mL. M / 532 mL

    M₂ = 1.9 M
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