75. In Canada and the United Kingdom, devices that measure blood glucose levels provide a reading in millimoles per liter. If a measurement of 5.3 mM is observed, what is the concentration of glucose (C6H12O6) in mg/dL?

The answer to this is the concentration of glucose (C6H12O6) in mg/dL = 95.48 mg/dL

Explanation:

To solve this we list out the known variables thus

Measured concentration of glucose (C6H12O6) = 5.3mM per liter

The molar mass of glucose = 180.156 g/mol

From the above, it is seen that one mole of glucose contains 180.156 grams of C6H12O6 therefore 5.3 mM which is 5.3 * 10⁻³ moles contains

5.3 * 10⁻³ moles * 180.156 g/mol = 0.9548 grams of glucose

Also 1 d L = 0.1 L or 1 L = 10 dL and 1 mg = 1000 g, hence

thus 0.9548 grams per liter is equivalent to 1000/10 * 0.9548 milligrams per dL or 95.48 mg/dL