Determine the work done by an ideal gas while expanding by a volume of 0.25 L against an external pressure of 1.50 atm (assume adiabatic conditions, i. e., no heat exchange during the expansion).

Answer : The value of work done by an ideal gas is, 37.9 J

Explanation:

Formula used:

Expansion work = External pressure of gas * Volume of gas

Expansion work = 1.50 atm * 0.25 L

Expansion work = 0.375 L. atm

Conversion used : (1 L. atm = 101.3 J)

Expansion work = 0.375 * 101.3 = 37.9 J

Therefore, the value of work done by an ideal gas is, 37.9 J