56. A gas has an initial volume of 2.50 L and

temperature of 45 °C. What is the temperature if

the volume is changed to 1.80 L?

T₂ = 228.96 k

Explanation:

Given data;

Initial volume = 2.50 L

Initial temperature = 45°C

Final volume = 1.80 L

Final temperature = ?

Solution;

(45+273 = 318 K)

According to charle's law,

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.80 L * 318 K / 2.50 L

T₂ = 572.4 L. K / 2.50 L

T₂ = 228.96 k