How many grams of oxygen are required to react with 2.7 g of dihydrogen sulfide

Mass = 3.84 g

Explanation:

Given dа ta:

Mass of hydrogen sulfide = 2.7 g

Mass of oxygen required = ?

Solution:

Chemical equation:

2H₂S + 3O₂ → 2H₂O + 2SO₂

Number of moles of hydrogen sulfide:

Number of moles = mass / molar mass

Number of moles = 2.7 g / 34 g/mol

Number of moles = 0.08 mol

Now we will compare the moles of hydrogen sulfide with oxygen.

H₂S : O₂

2 : 3

0.08 : 3/2 * 0.08 = 0.12 mol

Mass of oxygen;

Mass = number of moles * molar mass

Mass = 0.12 mol * 32 g/mol

Mass = 3.84 g