What is the volume of 7.50x10^24 molecules of NH3 at STP

V NH3 = 304.334 L

Explanation:

1 mol ≡ 6.02 E23 molecules

⇒ moles NH3 = (7.50 E24 molecules) * (mol/6.022 E23 molecules)

⇒ mole NH3 = 12.454 mol

assuming ideal gas:

PV = RTn

STP:

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

⇒ V NH3 = RTn/P

⇒ V NH3 = ((0.082 atm. L/K. mol) * (298 K) * (12.454 mol)) / (1 atm)

⇒ V NH3 = 304.334 L