A sample of oxygen occupies a volume of 160dm3 at 91 degrees Celsius. what will be the volume of the oxygen when the temperature drops to 0.00 degrees Celsius

V₂ = 120 dm³

Explanation:

Given dа ta:

Volume of oxygen = 160 dm³

Initial temperature = 91 °C

Final volume = ?

Final temperature = 0 °C

Solution:

First of all we will convert the temperature into kelvin.

91 + 273 = 364 k

0 + 273 = 273 K

According to Charle's law,

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 160 dm³ * 273 k / 364 k

V₂ = 43680 dm³. K / 364 k

V₂ = 120 dm³