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6 August, 12:33

A particular voltaic cell operates with the reaction: Zn (s) + Cl2 (g) - -->Zn^2 + (aq) + 2Cl^ - (aq) giving a cell potential of. 853 V. Calculate the amount of energy liberated from the cell when 20.0g of zinc metal is consumed?

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  1. 6 August, 16:02
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    The amount of energy liberated will be 49.38 J.

    Explanation:

    The amount of energy liberated (gibbs free energy) can be calculated using the following equation:

    ΔG° = - nFε

    n: amount of moles of electrons transfered

    F: Faraday's constant

    ε: cell potential

    20.0 g of Zn is equal to 0.30 mol.

    Two electrons are transfered during the reaction.

    Therefore, n = 2x0.30 ∴ n = 0.60

    ΔG° = - 0.60 x 96.485 x 0.853

    ΔG° = 49.38 J
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