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25 December, 12:53

How many liters of 0.50 KMnO4 solution can be produced from 0.5 L of a 3.0 M solution?

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  1. 25 December, 15:34
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    Answer: 3L

    Explanation:

    C1 = 3M

    V1 = 0.5

    C2 = 0.5M

    V2 = ?

    C1V1 = C2V2

    3x0.5 = 0.5 x V2

    V2 = (3x0.5) / 0.5 = 3L
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