Ask Question
30 August, 22:26

Aluminum had a specific heat of 0.215 cal / (g °C). When 25.7 cal (108.5 J) of heat is added to 18.4 g of aluminum at 20.0°C, what is the final temperature of the aluminum?

+3
Answers (1)
  1. 31 August, 01:31
    0
    26.5°C

    Explanation:

    Heat added is the product of mass, specific heat capacity, and change in temperature.

    q = mC (T - T₀)

    25.7 cal = (18.4 g) (0.215 cal/g/°C) (T - 20.0°C)

    T = 26.5°C
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Aluminum had a specific heat of 0.215 cal / (g °C). When 25.7 cal (108.5 J) of heat is added to 18.4 g of aluminum at 20.0°C, what is the ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers