A solution was prepared by mixing 0.5000 m hno2 with 0.380 m no2-. ka = 4.58 x 10-4. calculate the ph of the solution. show work.

pH of buffer can be calculated as:

pH=pKa+log[salt]/[Acid]

As ka = 4.58 x 10-4

Concentration of [Salt] that is NO2 (-1) = 0.380M

Concentration of [Acid] that is HNO2=0.500M

So, pH = - log (4.58*10^-4) + log ((0.380) / 0.500))

=3.21

So pH of solution will be 3.21