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17 February, 16:59

A gas occupies a volume of 8.60 L at 45C and 764 torr. What pressure would it occupy if the volume is adjusted to 13.3 L at 20C?

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  1. 17 February, 19:48
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    455 Torr

    Explanation:

    To get the correct answer, we employ the use of the General gas equation.

    In its general form, the General gas equation can be written as:

    P1V1/T1 = P2V2/T2

    Defining the parameters;

    P1 = 764 torr

    V1 = 8.6L

    T1 = 45 degrees Celsius = 273.15 + 45 = 318.15K

    P2 = ?

    V2 = 13.3L

    T2 = 20 degrees Celsius = 273.15 + 20 = 293.15K

    Rearranging the equation yields: P2 = P1V1T2/T1V2

    Substituting the values:

    P2 = (764 * 8.6 * 293.15) / (318.15 * 13.3)

    P2 = 455.2 Torr
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