How many liters of ammonia are required to change 34.9 L of nitrogen monoxide to nitrogen gas? Assume 100% yield and that all gases are measured at the same temperature and pressure.

23.27 L

Explanation:

The balanced reaction of ammonia and nitrogen monoxide is shown below as:

4NH₃ (g) + 6NO (g) ⇒ 5N₂ (g) + 6H₂O (l)

Given that:

Volume of nitrogen monoxide = 34.9 L

Since, temperature and pressure are same, volume coefficients would be same as equation coefficients.

So,

6 L of nitrogen monoxide reacts with 4 L of ammonia.

1 L of nitrogen monoxide reacts with 4/6 L of ammonia.

34.9 L of nitrogen monoxide reacts with (4/6) * 34.9 L of ammonia.

Amount of ammonia required = 23.27 L