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25 November, 17:20

g Given the reaction 4NH3 (g) 5O2 (g) - -> 4NO (g) 6H2O (g), what is the numerical value and sign in front of the change in [ammonia] over time for the rate expression of ammonia

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  1. 25 November, 21:01
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    Sign = Negative, since ammonia is a reactant.

    Value = 1 / 4 (Inverse of it's coefficient in the equation)

    Explanation:

    4NH3 (g) + 5O2 (g) - -> 4NO (g) + 6H2O (g)

    The Reaction Rate for a given chemical reaction is the measure of the change in concentration of the reactants or the change in concentration of the products per unit time.

    For a reaction of the form A+B→C

    the rate can be expressed in terms of the change in concentration of any of its components;

    rate = - Δ[A] / Δt

    rate = - Δ[B] / Δt

    rate = Δ[C] / Δt

    Considering a reaction in which the coefficients are different:

    A + 2B → 2D

    It is clear that [B] decreases two times as rapidly as [A], so in order to avoid ambiguity when expressing the rate in terms of different components, it is customary to divide each change in concentration by the appropriate coefficient:

    rate = - Δ[A] / Δt = - Δ[B] / 2Δt = Δ[D] / 2Δt

    Things to Note;

    - For products, the sign is always positive and for reactants, the sign is always negative.

    - The Numerical value is usually the inverse of the coefficient.

    Rate Expression of change in [ammonia] over time for the rate expression of ammonia:

    Sign = Negative, since ammonia is a reactant.

    Value = 1 / 4 (Inverse of it's coefficient in the equation)
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