What is the pressure exerted by 2.3 mol of a gas with a temperature of 40. °C and a volume of 3.5 L?

16.89 atm.

Explanation:

Step 1:

Data obtained from the question

Number of mole (n) = 2.3 mol

Temperature (T) = 40°C = 40°C + 273 = 313K

Volume (V) = 3.5L

Pressure (P) = ... ?

Gas constant (R) = 0.0821 atm. L/Kmol

The pressure exerted by the gas can be obtained by using the ideal gas equation as shown below:

PV = nRT

Divide both side by V

P = nRT / V

P = 2.3 x 0.0821 x 313 / 3.5

P = 16.89 atm.

Therefore, the pressure exerted by the gas is 16.89 atm.